(2b^2)-(9b)=5

Solution for (2b^2)-(9b)=5 equation:

Simplifying
(2b2) + -1(9b) = 5

Remove parenthesis around (9b)
(2b2) + -1 * 9b = 5

Multiply -1 * 9
(2b2) + -9b = 5

Reorder the terms:
-9b + (2b2) = 5

Solving
-9b + (2b2) = 5

Solving for variable 'b'.

Reorder the terms:
-5 + -9b + (2b2) = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + -9b + (2b2) = 0

Factor a trinomial.
(-1 + -2b)(5 + -1b) = 0

Subproblem 1
Set the factor '(-1 + -2b)' equal to zero and attempt to solve:

Simplifying
-1 + -2b = 0

Solving
-1 + -2b = 0

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -2b = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -2b = 0 + 1
-2b = 0 + 1

Combine like terms: 0 + 1 = 1
-2b = 1

Divide each side by '-2'.
b = -0.5

Simplifying
b = -0.5
Subproblem 2
Set the factor '(5 + -1b)' equal to zero and attempt to solve:

Simplifying
5 + -1b = 0

Solving
5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1b = 0 + -5
-1b = 0 + -5

Combine like terms: 0 + -5 = -5
-1b = -5

Divide each side by '-1'.
b = 5

Simplifying
b = 5
Solution
b = {-0.5, 5}